Python built-in function __call__() can make a class object callable like a function. Here is the tutorial:
Python __call__: Make a Class Instance Callable Like a Function – Python Tutorial
However, here is a problem: if the function parameters are changed, how to call it in __call__(). In this tutorial, we will discuss this topic.
Python __call__()
It is defined as:
def __call__(self, *args, **kwargs):
Here args and kwargs are dynamic parameters.
How to make __call() can call function with dynamic parameters
Here is an example:
class Test:
def __call__(self, *args, **kwargs):
self.forward(*args, **kwargs)
def forward(self, n1, n2, name = "add"):
print(n1, n2, name)
print(n1+n2)
t = Test()
t(3, 4, "sub")
t(3, 4, name = "addx")In this code, we use __call__() to call forward() function with *args, **kwargs.
Run this code, we will get:
3 4 sub 7 3 4 addx 7
We can find: parameters of forward() are changed, it can be called correctly by __call__().